浮点数求和 |
|
对于更快的版本,请参见 FloatSumFast
对于我的 C/C++ 版本,请参见 https://github.com/achan001/fsum
--[[ > fsum = require 'fsum' > = fsum(0.1, 0.1, 0.1, 0.1, 0.1, 0.1, 0.1, 0.1, 0.1, 0.1) - 1 0 > fadd, ftotal = fsum() > for i = 1, 10 do fadd(0.1) end > = ftotal() - 1 0 > ftotal(0) -- clear calculator > for i = 1, 10 do fadd(0.1) end > = ftotal() - 1 0 --]] local function fsum(...) local p, abs = {1}, math.abs -- p[1] == #p local function fadd(x) local p, i = p, 2 for j = 2, p[1] do local y = p[j] if abs(x) < abs(y) then x, y = y, x end local hi = x + y local lo = y - (hi - x) x = hi if lo ~= 0 then p[i] = lo; i = i + 1 end end if x - x ~= 0 then i = 2 end -- Inf or NaN p[1] = i p[i] = x end local function ftotal(clear) local p, x = p, 0 if clear then p[1] = 1 end -- ftotal(0) "clear" calculator for i = p[1], 2, -1 do -- sum in reverse local y = p[i] local hi = x + y local lo = y - (hi - x) x = hi if lo ~= 0 and i ~= 2 then -- check half way case if (lo < 0) == (p[i-1] < 0) then lo = lo * 2 -- |lo| = 1/2 ULP hi = x + lo -- -> x off 1 ULP if lo == hi - x then x = hi end end return x end end return x end if select('#', ...) == 0 then return fadd, ftotal end for i = 1, select('#', ...) do fadd(select(i, ...)) end return ftotal() end if select(1, ...) ~= 'fsum' then -- test code local read, fadd, ftotal = io.read, fsum() io.input(select(1, ...)) -- read from file pcall(function() while true do fadd(read('*n')) end end) print(ftotal()) end return fsum